It's just an equation. (I suppose a 12V car battery).

3s of starter, means 3*(900/12) C = 225C = 62.5mAh=0.0625Ah (900W is the
starter power).
Just add this to the loss of the battery.

Knowing that the alternator charges at 13.8V about 500W (500/(13.8-12)Â*
i.e. 200As=0.55Ah , it's easy.


Tom Del Rosso a écrit le 04/02/2019 Ã* 22:45Â*:
> If you turn over an engine periodically to keep it charged, how long do
> you run it to make up for the charge lost in starting?
>
> In this case it's my neighbor's 87 Buick Regal while he's in the
> hospital.
>
>